Kirchhoff’s Circuit Laws Explained

An Illustrated Guide to Kirchhoff’s Laws

Understanding the fundamental principles of circuit analysis.

Kirchhoff’s Current Law (KCL)

The Principle: The algebraic sum of currents entering a node (or junction) is zero.

In simple terms: What goes in must come out. The total current flowing into any point in a circuit must equal the total current flowing out of that point.

Analogy: Think of it like water pipes connected at a junction. The total amount of water flowing into the junction per second must be the same as the total amount flowing out.

Formula: Σ Iin = Σ Iout

KCL Examples (15 Examples)

Example 1: Find Ix

2A 3A Ix

In: 2A

Out: 3A, Ix

2 = 3 + Ix

Ix = -1A (meaning 1A flows in)

Example 2: Find Ix

5A 2A Ix 1A

In: 5A, 2A

Out: Ix, 1A

5 + 2 = Ix + 1

Ix = 6A

Example 3: Find Ia

10A Ia 4A 3A

In: 10A, Ia, 4A

Out: 3A

10 + Ia + 4 = 3

Ia = -11A (11A flows out)

Example 4: Find I1

I1 7A 12A

In: 12A

Out: I1, 7A

12 = I1 + 7

I1 = 5A

Example 5: Find Iy

6A 2A Iy

In: 6A

Out: 2A, Iy

6 = 2 + Iy

Iy = 4A

Example 6: Find Iz

15A 8A Iz

In: 15A

Out: 8A, Iz

15 = 8 + Iz

Iz = 7A

Example 7: All currents leaving

2A 5A Ix

In: 0

Out: 2A, 5A, Ix

0 = 2 + 5 + Ix

Ix = -7A (7A flows in)

Example 8: All currents entering

3A 4A Ix

In: 3A, 4A, Ix

Out: 0

3 + 4 + Ix = 0

Ix = -7A (7A flows out)

Example 9: Find Ib

1A 2A Ib 5A

In: 2A

Out: 1A, Ib, 5A

2 = 1 + Ib + 5

Ib = -4A (4A flows in)

Example 10: Find Ic

8A Ic 8A

In: 8A, 8A

Out: Ic

8 + 8 = Ic

Ic = 16A

Example 11: Find Id

Id 3A 9A

In: Id, 9A

Out: 3A

Id + 9 = 3

Id = -6A (6A flows out)

Example 12: Find Ie

12A Ie 12A

In: 12A

Out: Ie, 12A

12 = Ie + 12

Ie = 0A

Example 13: Find If

2A 3A 4A If

In: 2A, 3A

Out: 4A, If

2 + 3 = 4 + If

If = 1A

Example 14: Find Ig

Ig 5A 5A

In: Ig

Out: 5A, 5A

Ig = 5 + 5

Ig = 10A

Example 15: Find Ih

6A 2A Ih

In: 6A, 2A

Out: Ih

6 + 2 = Ih

Ih = 8A

Kirchhoff’s Voltage Law (KVL)

The Principle: The algebraic sum of all voltages around any closed loop in a circuit is equal to zero.

In simple terms: The voltage drops equal the voltage rises in any closed path. If you start at one point in a loop and measure the voltage changes as you go around, you’ll end up with the same voltage you started with.

Analogy: Imagine a roller coaster. You start at the bottom, the lift hill (voltage source) takes you up (voltage rise). As you go through the loops and turns (resistors), you lose that height (voltage drops), and you end up back at the bottom where you started.

Formula: Σ V = 0 or Σ Vrises = Σ Vdrops

KVL Examples (15 Examples)

Example 16: Find VR2

+ 12V R1VR1=5V R2VR2=?

Loop direction: Clockwise from source.

+12V – VR1 – VR2 = 0

+12V – 5V – VR2 = 0

VR2 = 7V

Example 17: Find VS

+ VS=? R1=3V R2=6V R3=2V

Loop direction: Clockwise.

+VS – 3V – 6V – 2V = 0

VS – 11V = 0

VS = 11V

Example 18: Find VR3

+ 24V R1=10V R2=8V R3=?

Loop direction: Clockwise.

+24V – 10V – 8V – VR3 = 0

6V – VR3 = 0

VR3 = 6V

Example 19: Opposing Source

+ 20V R1=8V + 5V R2=?

Loop direction: Clockwise.

+20V – 8V + 5V – VR2 = 0

17V – VR2 = 0

VR2 = 17V

Example 20: Find VR1

+ 9V R1=? R2=4V

Loop direction: Clockwise.

+9V – VR1 – 4V = 0

5V – VR1 = 0

VR1 = 5V

Example 21: Aiding Sources

+ 10V R1=? + 5V R2=12V

Loop direction: Clockwise.

+10V – VR1 – 5V – 12V = 0

-7V – VR1 = 0

VR1 = -7V (Polarity is reversed)

Example 22: Find VS2

+ 50V R1=20V + VS2=? R2=15V

Loop direction: Clockwise.

+50V – 20V + VS2 – 15V = 0

15V + VS2 = 0

VS2 = -15V

Example 23: Find VR2

+ 18V R2=? R1=18V

Loop direction: Clockwise.

+18V – VR2 – 18V = 0

-VR2 = 0

VR2 = 0V

Example 24: Find VS (Counter-Clockwise)

+ VS=? R1=7V R2=3V

Loop direction: Counter-Clockwise.

+3V + 7V – VS = 0

10V – VS = 0

VS = 10V

Example 25: Find Vx

+ 40V R1=15V R2=Vx R3=15V

Loop direction: Clockwise.

+40V – 15V – Vx – 15V = 0

10V – Vx = 0

Vx = 10V

Example 26: Unknown Source Polarity

? VS R1=5V R2=5V

Assume VS is a rise (CW). Current flows from R2 to R1.

+VS – 5V – 5V = 0

VS = 10V. Positive result means assumed polarity was correct (+ on top).

Example 27: Find VR3

+ 100V R1=25V R2=50V R3=?

Loop direction: Clockwise.

+100V – 25V – 50V – VR3 = 0

25V – VR3 = 0

VR3 = 25V

Example 28: Find VS1

+ VS1=? R1=12V + 3V R2=9V

Loop direction: Clockwise.

+VS1 – 12V + 3V – 9V = 0

VS1 – 18V = 0

VS1 = 18V

Example 29: Find VR1

+ 15V R1=? + 5V R2=5V

Loop direction: Clockwise.

+15V – VR1 – 5V – 5V = 0

5V – VR1 = 0

VR1 = 5V

Example 30: Find VR2

+ 6V R1=9V R2=?

Loop direction: Clockwise.

-6V – 9V – VR2 = 0

-15V – VR2 = 0

VR2 = -15V (Polarity is reversed)

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