Understanding the fundamental principles of circuit analysis.
The Principle: The algebraic sum of currents entering a node (or junction) is zero.
In simple terms: What goes in must come out. The total current flowing into any point in a circuit must equal the total current flowing out of that point.
Analogy: Think of it like water pipes connected at a junction. The total amount of water flowing into the junction per second must be the same as the total amount flowing out.
Formula: Σ Iin = Σ Iout
In: 2A
Out: 3A, Ix
2 = 3 + Ix
Ix = -1A (meaning 1A flows in)
In: 5A, 2A
Out: Ix, 1A
5 + 2 = Ix + 1
Ix = 6A
In: 10A, Ia, 4A
Out: 3A
10 + Ia + 4 = 3
Ia = -11A (11A flows out)
In: 12A
Out: I1, 7A
12 = I1 + 7
I1 = 5A
In: 6A
Out: 2A, Iy
6 = 2 + Iy
Iy = 4A
In: 15A
Out: 8A, Iz
15 = 8 + Iz
Iz = 7A
In: 0
Out: 2A, 5A, Ix
0 = 2 + 5 + Ix
Ix = -7A (7A flows in)
In: 3A, 4A, Ix
Out: 0
3 + 4 + Ix = 0
Ix = -7A (7A flows out)
In: 2A
Out: 1A, Ib, 5A
2 = 1 + Ib + 5
Ib = -4A (4A flows in)
In: 8A, 8A
Out: Ic
8 + 8 = Ic
Ic = 16A
In: Id, 9A
Out: 3A
Id + 9 = 3
Id = -6A (6A flows out)
In: 12A
Out: Ie, 12A
12 = Ie + 12
Ie = 0A
In: 2A, 3A
Out: 4A, If
2 + 3 = 4 + If
If = 1A
In: Ig
Out: 5A, 5A
Ig = 5 + 5
Ig = 10A
In: 6A, 2A
Out: Ih
6 + 2 = Ih
Ih = 8A
The Principle: The algebraic sum of all voltages around any closed loop in a circuit is equal to zero.
In simple terms: The voltage drops equal the voltage rises in any closed path. If you start at one point in a loop and measure the voltage changes as you go around, you’ll end up with the same voltage you started with.
Analogy: Imagine a roller coaster. You start at the bottom, the lift hill (voltage source) takes you up (voltage rise). As you go through the loops and turns (resistors), you lose that height (voltage drops), and you end up back at the bottom where you started.
Formula: Σ V = 0 or Σ Vrises = Σ Vdrops
Loop direction: Clockwise from source.
+12V – VR1 – VR2 = 0
+12V – 5V – VR2 = 0
VR2 = 7V
Loop direction: Clockwise.
+VS – 3V – 6V – 2V = 0
VS – 11V = 0
VS = 11V
Loop direction: Clockwise.
+24V – 10V – 8V – VR3 = 0
6V – VR3 = 0
VR3 = 6V
Loop direction: Clockwise.
+20V – 8V + 5V – VR2 = 0
17V – VR2 = 0
VR2 = 17V
Loop direction: Clockwise.
+9V – VR1 – 4V = 0
5V – VR1 = 0
VR1 = 5V
Loop direction: Clockwise.
+10V – VR1 – 5V – 12V = 0
-7V – VR1 = 0
VR1 = -7V (Polarity is reversed)
Loop direction: Clockwise.
+50V – 20V + VS2 – 15V = 0
15V + VS2 = 0
VS2 = -15V
Loop direction: Clockwise.
+18V – VR2 – 18V = 0
-VR2 = 0
VR2 = 0V
Loop direction: Counter-Clockwise.
+3V + 7V – VS = 0
10V – VS = 0
VS = 10V
Loop direction: Clockwise.
+40V – 15V – Vx – 15V = 0
10V – Vx = 0
Vx = 10V
Assume VS is a rise (CW). Current flows from R2 to R1.
+VS – 5V – 5V = 0
VS = 10V. Positive result means assumed polarity was correct (+ on top).
Loop direction: Clockwise.
+100V – 25V – 50V – VR3 = 0
25V – VR3 = 0
VR3 = 25V
Loop direction: Clockwise.
+VS1 – 12V + 3V – 9V = 0
VS1 – 18V = 0
VS1 = 18V
Loop direction: Clockwise.
+15V – VR1 – 5V – 5V = 0
5V – VR1 = 0
VR1 = 5V
Loop direction: Clockwise.
-6V – 9V – VR2 = 0
-15V – VR2 = 0
VR2 = -15V (Polarity is reversed)