📚 Basic Concepts
Key Definitions
- Speed: Distance covered per unit time
- Time: Duration taken to cover a distance
- Distance: Length of path covered
- Velocity: Speed with direction (for competitive exams, often treated same as speed)
Fundamental Formulas
Speed = Distance ÷ Time
Distance = Speed × Time
Time = Distance ÷ Speed
Units and Conversions
- Speed Units: km/hr, m/s, mph
- Key Conversion: 1 km/hr = 5/18 m/s
- To convert:
- km/hr to m/s: multiply by 5/18
- m/s to km/hr: multiply by 18/5
Important Principles
- Average Speed = Total Distance ÷ Total Time
- Relative Speed (same direction) = |S₁ – S₂|
- Relative Speed (opposite direction) = S₁ + S₂
🔄 Essential Formulas
Basic Speed Conversions
- km/hr to m/s: Speed × (5/18)
- m/s to km/hr: Speed × (18/5)
- Quick trick: km/hr to m/s → divide by 3.6
Relative Speed
- Same Direction: Faster speed – Slower speed
- Opposite Direction: Speed₁ + Speed₂
- Meeting Time = Distance between them ÷ Relative speed
Average Speed
- For two speeds S₁ and S₂ over equal distances: Average Speed = (2 × S₁ × S₂) ÷ (S₁ + S₂)
📖 Type 1: Basic Speed, Time & Distance
Example 1
Problem: A car travels 240 km in 4 hours. What is its speed in km/hr and m/s?
Solution:
- Speed = Distance ÷ Time = 240 ÷ 4 = 60 km/hr
- In m/s = 60 × (5/18) = 60 × 5/18 = 16.67 m/s
Example 2
Problem: A train runs at 54 km/hr. How much distance will it cover in 20 minutes?
Solution:
- Time = 20 minutes = 20/60 = 1/3 hour
- Distance = Speed × Time = 54 × (1/3) = 18 km
Example 3
Problem: A person walks 15 km in 3 hours. At what speed should he walk to cover 25 km in 4 hours?
Solution:
- Current speed = 15 ÷ 3 = 5 km/hr
- Required speed = 25 ÷ 4 = 6.25 km/hr
- Increase needed = 6.25 – 5 = 1.25 km/hr
📖 Type 2: Relative Speed
Example 4
Problem: Two trains are moving in opposite directions at 60 km/hr and 40 km/hr. They cross each other in 9 seconds. Find the sum of their lengths.
Solution:
- Relative speed = 60 + 40 = 100 km/hr
- In m/s = 100 × (5/18) = 250/9 m/s
- Combined length = Speed × Time = (250/9) × 9 = 250 meters
Example 5
Problem: A faster train overtakes a slower train. Faster train: 80 km/hr, slower: 50 km/hr. Time to overtake = 36 seconds. Find combined length.
Solution:
- Relative speed = 80 – 50 = 30 km/hr
- In m/s = 30 × (5/18) = 25/3 m/s
- Combined length = (25/3) × 36 = 300 meters
Example 6
Problem: Two cars start from same point in opposite directions at 30 km/hr and 40 km/hr. After how much time will they be 210 km apart?
Solution:
- Relative speed = 30 + 40 = 70 km/hr
- Time = Distance ÷ Speed = 210 ÷ 70 = 3 hours
📖 Type 3: Trains Problems
Example 7
Problem: A 150m long train crosses a 250m platform in 20 seconds. Find the speed of train.
Solution:
- Total distance = Length of train + Length of platform = 150 + 250 = 400m
- Speed = 400 ÷ 20 = 20 m/s
- In km/hr = 20 × (18/5) = 72 km/hr
Example 8
Problem: A train 120m long running at 36 km/hr crosses a man running at 9 km/hr in opposite direction. Time to cross?
Solution:
- Train speed = 36 km/hr, Man speed = 9 km/hr
- Relative speed = 36 + 9 = 45 km/hr = 45 × (5/18) = 12.5 m/s
- Time = Distance ÷ Speed = 120 ÷ 12.5 = 9.6 seconds
Example 9
Problem: Two trains 140m and 160m long are running at 42 km/hr and 30 km/hr in same direction. Time for faster to overtake slower?
Solution:
- Relative speed = 42 – 30 = 12 km/hr = 12 × (5/18) = 10/3 m/s
- Combined length = 140 + 160 = 300m
- Time = 300 ÷ (10/3) = 300 × 3/10 = 90 seconds
📖 Type 4: Boats and Streams
Example 10
Problem: Speed of boat in still water = 15 km/hr, stream speed = 3 km/hr. Find downstream and upstream speeds.
Solution:
- Downstream speed = Boat speed + Stream speed = 15 + 3 = 18 km/hr
- Upstream speed = Boat speed – Stream speed = 15 – 3 = 12 km/hr
Example 11
Problem: A boat takes 2 hours downstream and 3 hours upstream to cover 24 km each way. Find boat speed and stream speed.
Solution:
- Let boat speed = b, stream speed = s
- Downstream: 24 = (b + s) × 2 → b + s = 12
- Upstream: 24 = (b – s) × 3 → b – s = 8
- Adding: 2b = 20 → b = 10 km/hr
- Subtracting: 2s = 4 → s = 2 km/hr
Example 12
Problem: Downstream speed = 20 km/hr, upstream speed = 10 km/hr. Find still water speed and stream speed.
Solution:
- Still water speed = (Downstream + Upstream) ÷ 2 = (20 + 10) ÷ 2 = 15 km/hr
- Stream speed = (Downstream – Upstream) ÷ 2 = (20 – 10) ÷ 2 = 5 km/hr
📖 Type 5: Average Speed
Example 13
Problem: A car covers first 100 km at 50 km/hr and next 100 km at 40 km/hr. Find average speed.
Solution:
- Time for first 100 km = 100 ÷ 50 = 2 hours
- Time for next 100 km = 100 ÷ 40 = 2.5 hours
- Total distance = 200 km, Total time = 4.5 hours
- Average speed = 200 ÷ 4.5 = 44.44 km/hr
Example 14
Problem: A person travels equal distances at 30 km/hr, 40 km/hr, and 60 km/hr. Find average speed.
Solution:
- Let each distance = d
- Time₁ = d/30, Time₂ = d/40, Time₃ = d/60
- Total distance = 3d
- Total time = d/30 + d/40 + d/60 = d(4+3+2)/120 = 9d/120 = 3d/40
- Average speed = 3d ÷ (3d/40) = 40 km/hr
Example 15
Problem: Using formula for two equal distances at speeds S₁ and S₂: Average = (2×S₁×S₂)/(S₁+S₂)
For S₁ = 60 km/hr, S₂ = 40 km/hr: Average = (2×60×40)/(60+40) = 4800/100 = 48 km/hr
📖 Type 6: Races and Games
Example 16
Problem: In a 1000m race, A beats B by 100m. If A’s speed is 10 m/s, find B’s speed.
Solution:
- When A covers 1000m, B covers 900m
- Time taken by A = 1000 ÷ 10 = 100 seconds
- B’s speed = 900 ÷ 100 = 9 m/s
Example 17
Problem: A gives B a start of 20m in a 100m race and still beats him by 5 seconds. If A’s speed is 8 m/s, find B’s speed.
Solution:
- A covers 100m in 100 ÷ 8 = 12.5 seconds
- B covers 80m in 12.5 + 5 = 17.5 seconds
- B’s speed = 80 ÷ 17.5 = 4.57 m/s
Example 18
Problem: In a circular track of 400m, A and B start from same point in same direction. A’s speed = 8 m/s, B’s speed = 6 m/s. When will A lap B?
Solution:
- Relative speed = 8 – 6 = 2 m/s
- Time to gain one full lap = 400 ÷ 2 = 200 seconds
📖 Type 7: Meeting Point Problems
Example 19
Problem: Two persons A and B are 120 km apart. They start towards each other at 30 km/hr and 20 km/hr. Where and when do they meet?
Solution:
- Combined speed = 30 + 20 = 50 km/hr
- Time to meet = 120 ÷ 50 = 2.4 hours
- Distance covered by A = 30 × 2.4 = 72 km from A’s starting point
- Distance covered by B = 20 × 2.4 = 48 km from B’s starting point
Example 20
Problem: A starts from P to Q at 60 km/hr. After 2 hours, B starts from Q to P at 80 km/hr. Distance PQ = 480 km. When do they meet?
Solution:
- In 2 hours, A covers = 60 × 2 = 120 km
- Remaining distance = 480 – 120 = 360 km
- Combined speed = 60 + 80 = 140 km/hr
- Time to meet after B starts = 360 ÷ 140 = 18/7 hours
- Total time from A’s start = 2 + 18/7 = 32/7 hours ≈ 4.57 hours
📖 Type 8: Circular Motion
Example 21
Problem: Two runners on a 400m circular track start together. A runs at 8 m/s, B at 6 m/s in same direction. After how much time will A be exactly one lap ahead?
Solution:
- Relative speed = 8 – 6 = 2 m/s
- Time for A to gain 400m = 400 ÷ 2 = 200 seconds
Example 22
Problem: On a 200m circular track, two runners start from opposite points. A at 5 m/s, B at 3 m/s in same direction. When do they first meet?
Solution:
- Initial separation = 100m (half track)
- Relative speed = 5 – 3 = 2 m/s
- Time to meet = 100 ÷ 2 = 50 seconds
🎯 Quick Tips for Competitive Exams
Speed Conversion Shortcuts
- km/hr to m/s: Multiply by 5/18 or divide by 3.6
- m/s to km/hr: Multiply by 18/5 or multiply by 3.6
- Common conversions to remember:
- 18 km/hr = 5 m/s
- 36 km/hr = 10 m/s
- 54 km/hr = 15 m/s
- 72 km/hr = 20 m/s
Train Problems Quick Rules
- Crossing a pole/man: Distance = Length of train
- Crossing a platform: Distance = Length of train + Length of platform
- Two trains crossing: Distance = Sum of both train lengths
Boats and Streams Formulas
- Still water speed = (Downstream + Upstream) ÷ 2
- Stream speed = (Downstream – Upstream) ÷ 2
- Time ratio (Down:Up) = (b-s) : (b+s) where b=boat speed, s=stream speed
Average Speed Shortcuts
- For equal distances: Use harmonic mean formula
- For equal times: Simple arithmetic mean
- Remember: Average speed ≠ Average of speeds
Relative Speed Memory Tricks
- Same direction: Subtract (like chasing)
- Opposite direction: Add (like collision)
- Meeting problems: Always use combined speed
📊 Important Patterns & Ratios
Common Speed Ratios
- If speeds are in ratio 3:4, times are in ratio 4:3
- If A is 25% faster than B, speed ratio = 5:4, time ratio = 4:5
- If A is 20% slower than B, speed ratio = 4:5, time ratio = 5:4
Distance-Time Relationships
- Distance ∝ Speed (when time is constant)
- Distance ∝ Time (when speed is constant)
- Speed ∝ 1/Time (when distance is constant)
Train Length Patterns
- Most train problems use lengths: 100m, 120m, 150m, 200m, 250m
- Platform lengths: 150m, 200m, 250m, 300m, 400m
📝 Practice Problems
Set A – Basic Problems
- Convert 108 km/hr to m/s
- A car travels 180 km in 3 hours. Find speed in m/s
- At 45 km/hr, how much distance in 24 minutes?
Set B – Trains & Relative Speed
- 200m train crosses 150m platform in 14 seconds. Find speed in km/hr
- Two trains 120m and 80m long, speeds 54 km/hr and 36 km/hr, same direction. Overtaking time?
- Train 150m long crosses a man in 18 seconds. Speed of train?
Set C – Boats & Streams
- Boat speed 12 km/hr, stream 2 km/hr. Time to go 28 km downstream?
- Downstream 15 km/hr, upstream 9 km/hr. Still water and stream speeds?
- 24 km downstream in 2 hrs, same distance upstream in 3 hrs. Find speeds.
Set D – Average Speed & Complex
- First half distance at 40 km/hr, second half at 60 km/hr. Average speed?
- A and B are 300 km apart, approach each other at 80 km/hr and 70 km/hr. Meeting time and point?
- Circular track 500m, A at 10 m/s, B at 8 m/s, same direction from same point. When does A lap B?
🏆 Answer Key
Set A: 1) 30 m/s 2) 16.67 m/s 3) 18 km Set B: 4) 90 km/hr 5) 40 seconds 6) 30 km/hr Set C: 7) 2 hours 8) Still: 12 km/hr, Stream: 3 km/hr 9) Boat: 10 km/hr, Stream: 2 km/hr Set D: 10) 48 km/hr 11) 2 hours, 160 km from A’s start 12) 250 seconds
🔍 Common Exam Mistakes to Avoid
- Unit confusion: Always check if answer needed in km/hr or m/s
- Relative speed direction: Same vs opposite direction
- Train problems: Including/excluding platform length
- Average speed: Using arithmetic mean instead of harmonic mean
- Time calculation: Converting minutes to hours or vice versa
*Master these concepts with regular practice. Focus on speed and accuracy for competitive
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