Class 12 Physics Concepts
Master the Flow of Electric Charge
Q = ne
Where: Q = charge, n = number of electrons, e = 1.6 × 10⁻¹⁹ C
F = k(q₁q₂)/r²
Where: k = 9 × 10⁹ Nm²/C², r = distance between charges
E = F/q = kQ/r²
Unit: N/C or V/m
V = W/q = kQ/r
Unit: Volt (V) = Joule/Coulomb
E = -dV/dr
For uniform field: E = V/d
C = Q/V
Unit: Farad (F) = Coulomb/Volt
1/C = 1/C₁ + 1/C₂ + …
Same charge, different voltages
C = C₁ + C₂ + …
Same voltage, different charges
I = Q/t = nAve
Unit: Ampere (A) = Coulomb/second
V = IR
Where: V = Voltage, I = Current, R = Resistance
R = R₁ + R₂ + …
Same current, different voltages
1/R = 1/R₁ + 1/R₂ + …
Same voltage, different currents
ΣI = 0
Sum of currents at a node = 0
ΣV = 0
Sum of voltages in a loop = 0
P = VI = I²R = V²/R
Unit: Watt (W) = Joule/second
H = I²Rt = VIt = V²t/R
Unit: Joule (J)
V = ε – Ir
Where: ε = EMF, r = internal resistance
ε = ε₁ + ε₂ + …
r = r₁ + r₂ + …
ε = ε₁ = ε₂ = …
1/r = 1/r₁ + 1/r₂ + …
R₁/R₂ = R₃/R₄
No current through galvanometer
V ∝ L
Potential difference ∝ Length of wire
R = R₀(1 + αΔT)
α = temperature coefficient of resistance
vd = I/(nAe)
Where: n = electron density, A = area, e = electron charge
σ = 1/ρ = nμe
σ = conductivity, ρ = resistivity, μ = mobility
Reading: First two bands = significant figures, Third band = multiplier, Fourth band = tolerance
Coulomb (C)
e = 1.6 × 10⁻¹⁹ C
Volt (V)
1 V = 1 J/C
Ampere (A)
1 A = 1 C/s
Ohm (Ω)
1 Ω = 1 V/A
k = 9 × 10⁹ Nm²/C², ε₀ = 8.85 × 10⁻¹² C²/Nm²
Understand concepts clearly
Derive important formulas
Practice variety of problems
Master formula applications
V-I characteristics
Power curves
Wheatstone bridge
Potentiometer
Master these concepts for success in physics and engineering!